Integrand size = 20, antiderivative size = 49 \[ \int \frac {\frac {b B}{3}+B \sin (x)}{3+b \sin (x)} \, dx=\frac {B x}{b}-\frac {2 \sqrt {9-b^2} B \arctan \left (\frac {b+3 \tan \left (\frac {x}{2}\right )}{\sqrt {9-b^2}}\right )}{3 b} \]
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Time = 0.06 (sec) , antiderivative size = 54, normalized size of antiderivative = 1.10, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {2814, 2739, 632, 210} \[ \int \frac {\frac {b B}{3}+B \sin (x)}{3+b \sin (x)} \, dx=\frac {B x}{b}-\frac {2 B \sqrt {a^2-b^2} \arctan \left (\frac {a \tan \left (\frac {x}{2}\right )+b}{\sqrt {a^2-b^2}}\right )}{a b} \]
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Rule 210
Rule 632
Rule 2739
Rule 2814
Rubi steps \begin{align*} \text {integral}& = \frac {B x}{b}-\frac {\left (a B-\frac {b^2 B}{a}\right ) \int \frac {1}{a+b \sin (x)} \, dx}{b} \\ & = \frac {B x}{b}-\frac {\left (2 \left (a B-\frac {b^2 B}{a}\right )\right ) \text {Subst}\left (\int \frac {1}{a+2 b x+a x^2} \, dx,x,\tan \left (\frac {x}{2}\right )\right )}{b} \\ & = \frac {B x}{b}+\frac {\left (4 \left (a B-\frac {b^2 B}{a}\right )\right ) \text {Subst}\left (\int \frac {1}{-4 \left (a^2-b^2\right )-x^2} \, dx,x,2 b+2 a \tan \left (\frac {x}{2}\right )\right )}{b} \\ & = \frac {B x}{b}-\frac {2 \sqrt {a^2-b^2} B \arctan \left (\frac {b+a \tan \left (\frac {x}{2}\right )}{\sqrt {a^2-b^2}}\right )}{a b} \\ \end{align*}
Time = 0.13 (sec) , antiderivative size = 48, normalized size of antiderivative = 0.98 \[ \int \frac {\frac {b B}{3}+B \sin (x)}{3+b \sin (x)} \, dx=\frac {B \left (3 x-2 \sqrt {9-b^2} \arctan \left (\frac {b+3 \tan \left (\frac {x}{2}\right )}{\sqrt {9-b^2}}\right )\right )}{3 b} \]
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Time = 0.72 (sec) , antiderivative size = 67, normalized size of antiderivative = 1.37
method | result | size |
default | \(\frac {2 B \left (\frac {\left (-a^{2}+b^{2}\right ) \arctan \left (\frac {2 a \tan \left (\frac {x}{2}\right )+2 b}{2 \sqrt {a^{2}-b^{2}}}\right )}{b \sqrt {a^{2}-b^{2}}}+\frac {a \arctan \left (\tan \left (\frac {x}{2}\right )\right )}{b}\right )}{a}\) | \(67\) |
risch | \(\frac {B x}{b}+\frac {\sqrt {-a^{2}+b^{2}}\, B \ln \left ({\mathrm e}^{i x}+\frac {i a -\sqrt {-a^{2}+b^{2}}}{b}\right )}{b a}-\frac {\sqrt {-a^{2}+b^{2}}\, B \ln \left ({\mathrm e}^{i x}+\frac {i a +\sqrt {-a^{2}+b^{2}}}{b}\right )}{b a}\) | \(103\) |
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Time = 0.27 (sec) , antiderivative size = 163, normalized size of antiderivative = 3.33 \[ \int \frac {\frac {b B}{3}+B \sin (x)}{3+b \sin (x)} \, dx=\left [\frac {2 \, B a x + \sqrt {-a^{2} + b^{2}} B \log \left (\frac {{\left (2 \, a^{2} - b^{2}\right )} \cos \left (x\right )^{2} - 2 \, a b \sin \left (x\right ) - a^{2} - b^{2} + 2 \, {\left (a \cos \left (x\right ) \sin \left (x\right ) + b \cos \left (x\right )\right )} \sqrt {-a^{2} + b^{2}}}{b^{2} \cos \left (x\right )^{2} - 2 \, a b \sin \left (x\right ) - a^{2} - b^{2}}\right )}{2 \, a b}, \frac {B a x + \sqrt {a^{2} - b^{2}} B \arctan \left (-\frac {a \sin \left (x\right ) + b}{\sqrt {a^{2} - b^{2}} \cos \left (x\right )}\right )}{a b}\right ] \]
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Leaf count of result is larger than twice the leaf count of optimal. 170 vs. \(2 (41) = 82\).
Time = 12.79 (sec) , antiderivative size = 170, normalized size of antiderivative = 3.47 \[ \int \frac {\frac {b B}{3}+B \sin (x)}{3+b \sin (x)} \, dx=\begin {cases} \text {NaN} & \text {for}\: a = 0 \wedge b = 0 \\- \frac {B \cos {\left (x \right )}}{a} & \text {for}\: b = 0 \\\frac {B x}{b} & \text {for}\: a = - b \vee a = b \\- \frac {B a \log {\left (\tan {\left (\frac {x}{2} \right )} + \frac {b}{a} - \frac {\sqrt {- a^{2} + b^{2}}}{a} \right )}}{b \sqrt {- a^{2} + b^{2}}} + \frac {B a \log {\left (\tan {\left (\frac {x}{2} \right )} + \frac {b}{a} + \frac {\sqrt {- a^{2} + b^{2}}}{a} \right )}}{b \sqrt {- a^{2} + b^{2}}} + \frac {B x}{b} + \frac {B b \log {\left (\tan {\left (\frac {x}{2} \right )} + \frac {b}{a} - \frac {\sqrt {- a^{2} + b^{2}}}{a} \right )}}{a \sqrt {- a^{2} + b^{2}}} - \frac {B b \log {\left (\tan {\left (\frac {x}{2} \right )} + \frac {b}{a} + \frac {\sqrt {- a^{2} + b^{2}}}{a} \right )}}{a \sqrt {- a^{2} + b^{2}}} & \text {otherwise} \end {cases} \]
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Exception generated. \[ \int \frac {\frac {b B}{3}+B \sin (x)}{3+b \sin (x)} \, dx=\text {Exception raised: ValueError} \]
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Time = 0.28 (sec) , antiderivative size = 73, normalized size of antiderivative = 1.49 \[ \int \frac {\frac {b B}{3}+B \sin (x)}{3+b \sin (x)} \, dx=\frac {B x}{b} - \frac {2 \, {\left (B a^{2} - B b^{2}\right )} {\left (\pi \left \lfloor \frac {x}{2 \, \pi } + \frac {1}{2} \right \rfloor \mathrm {sgn}\left (a\right ) + \arctan \left (\frac {a \tan \left (\frac {1}{2} \, x\right ) + b}{\sqrt {a^{2} - b^{2}}}\right )\right )}}{\sqrt {a^{2} - b^{2}} a b} \]
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Time = 8.27 (sec) , antiderivative size = 94, normalized size of antiderivative = 1.92 \[ \int \frac {\frac {b B}{3}+B \sin (x)}{3+b \sin (x)} \, dx=\frac {2\,B\,\mathrm {atan}\left (\frac {\sin \left (\frac {x}{2}\right )}{\cos \left (\frac {x}{2}\right )}\right )}{b}+\frac {2\,B\,\mathrm {atanh}\left (\frac {-\sin \left (\frac {x}{2}\right )\,a^2+\cos \left (\frac {x}{2}\right )\,a\,b+2\,\sin \left (\frac {x}{2}\right )\,b^2}{\sqrt {b^2-a^2}\,\left (2\,b\,\sin \left (\frac {x}{2}\right )+a\,\cos \left (\frac {x}{2}\right )\right )}\right )\,\sqrt {b^2-a^2}}{a\,b} \]
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